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Geometry

Vertex Form Calculator calculator

Rewrites a quadratic from standard form into vertex form a(x-h)²+k, with the vertex shown.

Published 21 August 2026

What this calculator does

Vertex form rewrites a quadratic as a(x − h)² + k instead of ax² + bx + c. What is vertex form good for: the pair (h, k) is the vertex of the parabola sitting in plain sight, rather than something you have to compute separately, and the shape of the equation itself tells you how the graph has been stretched and shifted from the plain y = x².

This calculator takes the standard-form coefficients a, b and c and rewrites the whole equation in vertex form quadratic notation, not just the numeric vertex point. It does this by completing the square: h = −b/2a and k = c − b²/4a, the same two values that also answer where the parabola turns.

The formula

Formulah = −b/2a, k = c − b²/4a, so ax²+bx+c = a(x−h)² + k

Completing the square on ax² + bx + c factors out a, adds and subtracts (b/2a)² inside the brackets, and collects the leftover constant outside. That leaves a(x − h)² + k with h = −b/(2a) and k = c − b²/(4a). Because a is unchanged, the parabola opens upward when a is positive and downward when a is negative, exactly as it did in standard form.

TermMeaning
aThe leading coefficient. Controls how narrow or wide the parabola is, and which way it opens.
hThe x-coordinate of the vertex: h = −b/(2a).
kThe y-coordinate of the vertex: k = c − b²/(4a).
Axis of symmetryThe vertical line x = h that the parabola is a mirror image across.

The inputs explained

FieldWhat to enter
aThe coefficient of x². Cannot be zero, or the equation is a straight line, not a quadratic.
bThe coefficient of x.
cThe constant term.

When to use it

Finding the maximum or minimum of a quadratic

Vertex form puts the turning point straight into the equation, which is often the actual question behind a word problem about maximum height, minimum cost or peak profit.

Sketching a parabola by hand

Knowing h, k and the direction it opens is usually enough to sketch a reasonable graph without plotting a table of points first.

Checking algebra homework on completing the square

Completing the square by hand is easy to get slightly wrong on the sign of h. Running the same a, b, c through here checks the working without redoing it from scratch.

Worked examples

Every figure in the tables below is produced by this page’s own calculator at build time, so the numbers and the tool always agree. Select any row to load that scenario.

How the vertex form changes as a changes, with b and c fixed

The coefficient a stretched, flattened and flipped, with b and c held at 8 and 3.

b = 8, c = 3 held fixed
aVertex formVertex (h, k)
1(x + 4.000)² − 13.000(-4.000, -13.000)
22.000(x + 2.000)² − 5.000(-2.000, -5.000)
33.000(x + 1.333)² − 2.333(-1.333, -2.333)
-1−(x − 4.000)² + 19.000(4.000, 19.000)
-2-2.000(x − 2.000)² + 11.000(2.000, 11.000)
0.50.5000(x + 8.000)² − 29.000(-8.000, -29.000)
The vertex x-coordinate, h, moves as a changes because h = −b/(2a) depends on a: at a = 1 the vertex sits at x = −4, but at a = 3 it moves to x ≈ −1.333, purely from the same b being divided by a larger a. Flipping the sign of a (from 2 to −2) flips the parabola from opening upward to opening downward, and moves the vertex from a minimum to a maximum.

How the vertex form changes as c changes, with a and b fixed

The constant term c shifted up and down, with a and b held at 1 and −4.

a = 1, b = −4 held fixed
cVertex formVertex (h, k)
0(x − 2.000)² − 4.000(2.000, -4.000)
2(x − 2.000)² − 2.000(2.000, -2.000)
4(x − 2.000)²(2.000, 0)
6(x − 2.000)² + 2.000(2.000, 2.000)
-2(x − 2.000)² − 6.000(2.000, -6.000)
-4(x − 2.000)² − 8.000(2.000, -8.000)
The vertex x-coordinate stays fixed at x = 2 throughout, because h = −b/(2a) does not involve c at all. Only k moves, sliding the whole parabola straight up or down as c changes: at c = 4 the vertex sits exactly on the x-axis, at k = 0.

Questions

What is vertex form?

Vertex form writes a quadratic as a(x − h)² + k, where (h, k) is the vertex of the parabola and a controls its width and direction. It is an alternative to standard form, ax² + bx + c, that makes the turning point visible directly in the equation.

How do you convert a quadratic vertex form equation back to standard form?

Expand the squared bracket: a(x − h)² + k becomes ax² − 2ahx + ah² + k. Matching that against ax² + bx + c gives b = −2ah and c = ah² + k, which recovers the original standard-form coefficients.

Does vertex form give the same roots as standard form?

Yes, both forms describe exactly the same parabola, just written differently. The quadratic equation calculator solves for the roots and numeric vertex directly from standard form if that is what you need.

Why does completing the square work?

Adding and subtracting (b/2a)² inside the expression does not change its value, but it lets the x² and x terms be regrouped into a perfect square, a(x − h)², with everything left over collected into the constant k.

For the roots and discriminant of the same quadratic, see the quadratic equation calculator. To evaluate a general exponent or root, see the exponents and roots calculator.